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Little Richard

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  1. Are you from Belgium? How are the living expenses? Are you employed? It sounds great, except how do you make ends meet?
  2. So I received an invitation for Emory's recruitment weekend. Given I've never done something like this before, I don't know what proper attire would be. Are we talking suits or something a little less dressy? It'd be great to hear from people who have done this before. Apologies if this topic has been discussed already. Thanks
  3. Congrats to both of you -- I received an Emory invitation, too!!
  4. Ohh, okay. I feel silly that it's so basic but the complexity must have thrown me off. Thanks to both of you!
  5. Hello, everyone. I am writing about a problem in the first practice test of the ETS Guide to the GRE, second edition. ON page 44 they give two overlapping circles and within the overlap a diamond. The diamond's top and bottom points are at the points of where the circles' sides intersect, and the left and right points rest on points O and P. The question asks, "In the figure above, O and P (left and right points of the diamond) are centers of the two circles. If each circle has radius R, what is the area of the shaded region?" If you have solved this problem, let me know how. Because I will explain how I did it, and it looks like ETS made a typo. I can reason that the diamond has all equal sides; each line originates from the center and goes to the circle's edge. So we need to find the area of the diamond whose perimeter is 4R, right? If we cut that diamond in half we get two equilateral triangles, each side being R. To find the area of one half of the diamond, an equilateral triangle, we need 1/2 x base x height. The base is r. The height, using the proportions of a 30:60:90 triangle is r/2 x Sq.r. 3 So the area of one of the equilateral triangles is then: (r x r/2[sq.r.3])/2 or, simplified, ([r^2]/2 x sq.r.3) / 2 We multiply that by 2, to get the area of the entire diamond, and it becomes (r^2)/2 x sq.r. 3, right? The correct answer is, according to ETS, r^2 x (sq.r.3)/2 so the division by two is placed under the square root of 3 rather than r^2, which seems like a typo to me, and I cannot reason how to get that answer. However, math also is not my strength. Someone help?
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