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Special relativity


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"GPS satellites orbit the earth at a speed of approximately 3900 m/s, compared to our speed on the earth's surface of 460 m/s at the equator. This means that the clocks on the satellites must be adjusted by --- seconds each day to match the clocks on the earth's surface."

I tried to solve this question by determining the relative velocity:

vr= v1 + v2/ 1+ (v1)(v2)/c^2 which got me 2.4x10^-3 m/s.

I then used t=to/ √ 1-vr^2/c^2 where to is the number of seconds there are on earth in a day (86400), but the issue is I keep getting 86400 as my answer even though it's wrong.

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