regularhumanbeing Posted August 3, 2013 Share Posted August 3, 2013 Took the GRE today and one question on the Quant section I'm still struggling to figure out, wondered if any geniuses here could explain this one to me. 3 to the 82nd power divided by 5 leaves what remainder? It was a multiple choice, not a quant comp, so somehow you were expected to deduce this answer. For the life of me, I can't figure it out. I've since written a computer program to output all the remainders from 3 to the 0 to 3 to the 82nd power but I can't see any pattern here, nor can I brainstorm any way to simplify this question. Any insights would at least give me peace of mind, although not change my score. Thanks for your help. Cesare 1 Link to comment Share on other sites More sharing options...
DerpTastic Posted August 3, 2013 Share Posted August 3, 2013 (edited) Without a calculator, there actually is a pattern here that can be used. Each time the power is raised the remainder will also change, but it should follow a pattern. 3 ^ 1 / 5 : Remainder of 3 3 ^ 2 / 5 : Remainder of 4 3 ^ 3 / 5 : Remainder of 2 3 ^ 4 / 5 : Remainder of 1 3 ^ 5 / 5 : Remainder of 3 3 ^ 6 / 5 : Remainder of 4 3 ^ 7 / 5 : Remainder of 2 3 ^ 8 / 5 : Remainder of 1 3 ^ 9 / 5 : Remainder of 3 As it's following a pattern, it goes 4 cycles then repeats. Just looking at the pattern quickly, 82 is an even power, so it would be either a remainder of 4 or 1, and because 82 is not divisible by 4, it lines up with answers like 3^2 and 3^6, so it must have a remainder of 4? Edited August 3, 2013 by DerpTastic Arezoo, Cesare and music 3 Link to comment Share on other sites More sharing options...
MikKar Posted August 3, 2013 Share Posted August 3, 2013 (edited) The units are cyclical after a power of 3, so that's all you need to know to figure out the remainder. n = 0 -> Unit is 1 (3^0 = 1) n = 1 -> Unit is 3 (3^1 = 3) n = 2 -> Unit is 9 (3^2 = 9) n = 3 -> Unit is 7 (3^3 = 27) n = 4 -> Unit is 1 (3^4 = 81) etc... For a power of 82, you just need to know that 3^2 and 3^82 will have the same unit in the end, which is 9. A division by 5 will result in a remainder of 4. Edit : Ah, DerpTastic beat me to it, haha Edited August 3, 2013 by MikKar Cesare and music 2 Link to comment Share on other sites More sharing options...
regularhumanbeing Posted August 3, 2013 Author Share Posted August 3, 2013 Ah. I started to do that, just didn't pick up the pattern correctly. Thanks for the peace of mind, it's much appreciated. Link to comment Share on other sites More sharing options...
33andathirdRPM Posted August 3, 2013 Share Posted August 3, 2013 http://en.wikipedia.org/wiki/Fermat%27s_little_theorem Link to comment Share on other sites More sharing options...
Guest Gnome Chomsky Posted August 4, 2013 Share Posted August 4, 2013 If you've ever taken discrete mathematics in college, they go over stuff like that. Especially when using modulus. Link to comment Share on other sites More sharing options...
andythemonster Posted August 8, 2013 Share Posted August 8, 2013 3^1, the unit digit is 3; 3^2, the unit digit is 9; 3^3, the unit digit is 7; 3^4, the unit digit is 1; 3^5, the unit digit is 3 again; .... since that repeats every 4, the unit digit of 3^82 must be 9; so, the remainder must be 4. andythemonster and vimleshgoesvroom 2 Link to comment Share on other sites More sharing options...
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